how to break the url and you keep all that after “?”

Question

Suppose there is url = https://.site.ru/index.php?id=5&v=3 , how to display all that after ? $get = "id=5&v=3" ;

I certainly understand the PHP tag, but url = https://.site.ru/index.php?id=5&v=3 not a PHP format, but the second piece is yes.
You did not try to enter the docks of PCPs, they are in Russian

teran teran 18k one 13 thirty · Accepted Answer · 2017-05-02T21:27:22

For example, so

 list(, $query) = explode('?', $url);

or so

 $uqery = parse_url($url, PHP_URL_QUERY);

teran

18k one 13 thirty

Thanks for the answer, I also tried to implement it, but I accidentally made a mistake and could not understand why it was not working, so I was asked a question. Thank you, everything works - Ruslan Liashenka

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kosiakMD kosiakMD 403 four 9 · Answer 2 · 2017-05-02T21:26:58

2 answers 2