RegExp: find the square bracket "[" if the word "foo" is not in front of it?
bar[ <--- это найти foo[ <--- а это не надо Thank!
- In js regex, there is no lookbehind, and without this, with a single expression you cannot correctly make a match - zb '
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1 answer
The regular expression will be like this
^(?!foo).*\[ On JS will be like this
var regexp = new RegExp("^(?!foo).*\\["); var string = 'bar['; console.log(string.search(regexp)); Farkhod Daniyarov Farkhod Daniyarov
1.569 1 golden mark 9 silver marks 18 bronze marks
var string = 'afoo[';- zb '- @zb '- It seems that the description says, find the square bracket "[" if the word "foo" is not in front of it? . If you have a working solution , discard it - Farkhod Daniyarov
- One regexp on js in any way, you need a backreference - zb '
- In fact, in such cases it is always important to know the source data and why to look for it - zb '
- @FarkhodDaniyarov why not so "(? <! Foo) [" you decided to write? I think this is more correct - Ilya Babushkin
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