Is it possible in python 2.7 in regex.findall () to find valid from one line to another? I now have a date that I need to sort out with regex.
UA.E.3858-17,23.05.2017, "Subsidiary Company", "Ukrmetrteststandard" "", RENAULT CLIO, M1,, 2013, VF17R040H49534950, b / c, euro-5,, https: //drive.google.com/ open? id = 0B48-MrZcy1-zT0V0YlZINGRsSFU, UA.E.3859-17,23.05.2017, "DP", "Ukrmetrteststandart" "" ", NISSAN MICRA, M1,, 2012, MDHFBUK13U0522453, b / c, euro-5 https://drive.google.com/open?id=0B48-MrZcy1-zV3RwLXlmdzk0dkE, UA.E.3860-17,23.05.2017, "Ukrmetrteststandart" "UR", CITROEN BERLINGO, N1, 2011, VF77N9HPP , b / c, Euro-5,, https: //drive.google.com/open? id = 0B48-MrZcy1-zODZpSGI5REVza3c, UA.E.3861-17,23.05.2017, "Ukrmetrteststandart" "" , NISSAN LEAF, M1,, 2015,1N4AZ0CP9FC323172, b / c, EL, https: //drive.google.com/open? Id = 0B48-MrZcy1-zejkxNFN0WXhhSUk, UA.E.3862-17,23.05.2017, "ДП" "Укрметртестстандарт" "", FIAT DOBLO, M1,, 2010, ZFA26300009062099, b / c, euro-5,, https: //drive.google.com/open? Id = 0B48-MrZcy1-zVkNQMERFR21XOGc, UA. E.3863-17.23.05.2017, "DP "" Ukrmetrteststandard "" ", AUDI S5 SPORTBACK, M1, 2012, WAUZZZ8T2CA027101, b / c, Euro-5,, https: //drive.google.com/open? Id = 0B48-MrZcy1-zSzVRa3VMcHVVVVVVCVVVV3VMcHVVVVVVVVVVVVVVVVVVVVVV3VV3VV3VVVVVVVV3VMcVVVV? .3864-17,23.05.2017, "ДП", "Ukrmetrteststandart" "", OPEL VIVARO, N1,, 2013, W0LF7B1BEDV610630, b / c, euro-5,, https: //drive.google.com/open? Id = 0B48-MrZcy1-zRmR2amNBSDJkRWs, UA.E.3865-17,23.05.2017, "ДП", "Ukrmetrteststandart" "", SKODA FABIA, M1,, 2011, TMBEM25J6B3178665, b / c, Євро-5,, https: /drive.google.com/open?id=0B48-MrZcy1-zaW9VdHJ1MTZUTGc, UA.E.3870-17,24.05.2017, "Ukrmetrteststandart" "", "NISSAN QUASHQAI, M1,, 2013, SJNFEAJ10U27044, NISSAN QUASHQAI, M1,, 2013, SJNFEAJ10U27044, NISSAN QUASHQAI, M1, 2015 to, Euro-5,, https: //drive.google.com/open? id = 0B48-MrZcy1-zM1BGcFhJLTZ0T00,
I need to go through with the "UA" to the special character "\ n". How can I do that?
re.findall(r'UA([^\n]+)\n', s, re.S & re.M)? - MaxU