I was sitting and inventing a puzzle in python. The essence is as follows. Team 1 scores in 3 cases out of 7 for example. Team 2 scores in 2 cases out of 6 for example. How to calculate the probability of winning one of the teams, if the number of attacks of each team is 10.

Perhaps an elementary question, but I will be happy for help) Thank you)

  • The task is pure turver. And no side to the python. Or on it it is necessary to pomontekarlit? - Akina

1 answer 1

Terver to help - http://www.matburo.ru/tv_spr_sub.php?p=1

well, just based on common sense: 3/7 = 0.44 2/6 = 0.33 from which, regardless of the number of attacks, the probability of winning a team 1 - 44% the probability of winning a team 2 - 33%

  • yeah well yes. and if one team scores in 6 out of 7 cases, and the second 5 out of 7 cases, then the probabilities are: 86 and 71%. yeah so be it. Thanks for the formulas - I found it myself. - Big Boss
  • Probability is not counted as a percentage. Someone cruelly deceived you. - Mikhail Alekseevich