Determine the bit rate (Mbps) of the data transmission channel required to watch online video (without delay).

  • Frame width W: 600.
  • Frame height H: 450.
  • Frame rate f: 24.
  • C: 24 color depth.
  • Audio format A: 2 channels.
  • Sample rate F *, kHz: 44.
  • The bit depth of the audio data is D: 24.

How can I determine?

  • It all depends on what codec the video will be encoded. In kaw-format, no normal person will transmit. - Yaant
  • Well, raw is just needed, that is, it is purely “virtual” - Ilya Burmaka
  • 2
    And, well, then just count it. Each frame must be 600 * 450 * 24 bits. Such frames per second must be transferred 24. That is, 600 * 450 * 24 * 24 = 155520000. Similarly, calculate for audio, add up, and convert to megabits. - Yaant

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