The scope of the variable, inside the function

Question

I don’t understand why I don’t see the $ a variable, if I’ve indicated that it is global, does it have to come from the scope of the inFoo function?

How then to address her?

function inFoo() { $a = 5; function foo() { global $a; return $a; } return foo(); } echo '<pre>'; print_r(inFoo()); echo '</pre>';

Accepted Answer · 2017-09-24T20:10:01

It is necessary to use closure and use :

 function inFoo() { $a = 5; $inner = function() use ($a) { return $a; }; return $inner(); }

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