Given a list filled with arbitrary integers.

Get a new list, the elements of which will be:

  1. non-duplicate elements of the source list: for example, lst = [1, 2, 4, 5, 6, 2, 5, 2] , you need to get lst2 = [1, 2, 4, 5, 6]

  2. elements of the original list that do not have repetitions: for example, lst = [1 , 2, 4, 5, 6, 2, 5, 2] , you need to get lst2 = [1, 4, 6] .

Closed due to the fact that off-topic participants Kromster , insolor , Suvitruf ♦ , freim , vmchar 1 Jun at 16:00 .

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1 answer 1

https://ideone.com/jSMiI2

 lst = [1, 2, 4, 5, 6, 2, 5, 2] used = set() unique = [x for x in lst if x not in used and (used.add(x) or True)] print(unique) from collections import Counter counter = Counter(lst) unique = list(counter) print(unique) single = [x for x,n in counter.items() if n==1] print(single)

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