There is a need to write a simple bash script, in a loop from 1 to X, that executes certain code, but this way:
#!/bin/bash for c in {1...5} do #some code done does not work, and so:
... for (( i=1 ; i < 5 ; i++ )) ... also. What to do? Bash version 4.4-5.
try this:
for num in 1 2 3 5 7 11 ; do echo $num ; done or so:
for num in $(seq 1 10) ; do echo $num ; done UPD:
In the script you can do this:
if [ $# -eq 0 ] ; then echo "to few args" && return 1; else for num in $(seq 1 $1) ; do echo $num ; done fi and then call:
./script.sh 5 >>> 1 2 3 4 5 
Source: https://ru.stackoverflow.com/questions/743367/
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for i in $(seq 1 4); do echo $i; donefor i in $(seq 1 4); do echo $i; done- vp_arth