Cauchy inequality in java

Question

There is a Cauchy inequality. The user sets the value n . Everything seems to be easy, but I can’t figure out how to write in such a way that the number a in the inequality changes from the entered n ( a is randomly obtained numbers).

@diraria function in the photo, I am sure that there is no way without arrays, but I have no idea how to do it.
the photo is not a function but an inequality) the function has parameters and a return value.
Tell me, please, what does the function accept and what should it return?
In the end, everything works like this: for the entered number "n", you need to check this statement (which is on the photo) in 1000 different sets.
The numbers "a" are randomly generated from 0 to 100. As a result, you need to display all the sets where the difference between the left and right sides of the inequality is less than 5%.

Maxim Stepanov Maxim Stepanov 992 four 15 · Accepted Answer · 2017-11-22T20:48:11

 int a; // рандомные числа int aIncr = 0; // здесь будет результат сложения всех "a" int aMult = 1; // здесь будет результат умножения всех "a" // Где-то получено значение "n" for(int i = 0; i < n; i++){ a = (рандомное число); aIncr += a; aMult *= a; }

It remains to replace the expressions in brackets with the variables "aIncr" and "aMult"

diraria diraria 8,329 four 14 45 · Answer 2 · 2017-11-22T21:02:11

As I understand it, the question is how to work with arrays.

You can create an array of a certain size like this:
```
 int[] array = new int[размер_массива]; 
```
the resulting array will be filled with zeros
You can refer to the element by index (array indices are numbers from zero to размер_массива - 1 ):
```
 array[индекс] 
```
You can run through the entire array using the for loop:
```
 for (int i = 0; i < array.length; ++i) ... 
```
For example, this is how you can get the sum of all the elements of an array:
```
 int sum = 0; for (int i = 0; i < array.length; ++i) sum += array[i]; 
```
(by the way, here are some more ways to find the sum of the elements of an array )

Thanks for the information and help, as far as I understood, I need to do this: I find the sum divided by "n" and the product offered by 1 / n, I compare them to the difference of inequality.
And I insert all this code into a loop that will be executed 1000 times.
And already from these 1000 cases I choose those that suit me (the difference is less than 5%).

Cauchy inequality in java

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