from re import * v=split(r"[\s,)(]", r"(C:\Users\Gleb\Desktop\сайты.txt,C:\Users\Gleb\Desktop\istock_000020116885large_-_copy-700x461.jpg)") print(v) The code displays:
['', 'C:\Users\Gleb\Desktop\сайты.txt', 'C:\Users\Gleb\Desktop\istock_000020116885large_-_copy-700x461.jpg', '']
And should display:
['C:\Users\Gleb\Desktop\сайты.txt', 'C:\Users\Gleb\Desktop\istock_000020116885large_-_copy-700x461.jpg']
Why so deduces?
You cut by given literals, this is exactly what a python does , on the one hand, the literal C , and on the other? Nothing - an empty string, so he inserts it.
To get what you need, you must tell the python what you want to get , not what you don't need .
In the comments, @ gil9red suggested a more regular expression:r"\w.+?\.\w+"
import re string = r"(C:\Users\Gleb\Desktop\сайты.txt,C:\Users\Gleb\Desktop\istock_000020116885large_-_copy-700x461.jpg)" regex = r"([\w\:\\\.\-]+)" print(re.findall(regex, string)) 
C: D: - gil9red.+? . The colon here is redundant, and in any case you do not screen it, it does not do what you expect. - Vasiliy Rusin\w: , then I’m not looking for all the characters ( .+? ) To the end of the file, by its suffix ( \.\w+ ). Therefore, I do not think that there is redundancy. It is clear that such a suffix can be found in the name of the folder, but there should be restrictions. In general, regarding redundancy, the same result can be achieved even easier. I will show in response - gil9redIn simple text processing cases, you can do without regulars:
text = r"(C:\Users\Gleb\Desktop\сайты.txt,C:\Users\Gleb\Desktop\istock_000020116885large_-_copy-700x461.jpg)" filename_list = text[1:-1].split(',') print(filename_list) Result:
['C:\\Users\\Gleb\\Desktop\\сайты.txt', 'C:\\Users\\Gleb\\Desktop\\istock_000020116885large_-_copy-700x461.jpg'] 
Source: https://ru.stackoverflow.com/questions/753225/
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strip()initially apply to a string or something. - Visman