Work with DXF. Python (Sorting coordinates from point of reference)

Question

There is a DXF file, I wrote a function that receives the coordinates of each point in this format:

 [ [0.0, 0.0, 0.0, 0.0, 10.0, 0.0], [0.0, 10.0, 0.0, 15.0, 10.0, 0.0], [15.0, 10.0, 0.0, 15.0, 10.0, 5.0], [15.0, 10.0, 5.0, 15.0, 13.0, 5.0] ]

Code:

 def getCoordinates(key): # Функция получает координаты XYZ, по ключу # "AcDbLine\n" - линия, "AcDbPoint\n" - точка ind = [] CoordList = [] for n, e in enumerate(ll): if key in e: ind.append(n) for sp in ind: a = ll[sp + 2:sp + 13] try: # Если это линия, то взять координаты начальной и конечно точек CoordList.append([float(a[0]), float(a[2]), float(a[4]), float(a[6]), float(a[8]), float(a[10])]) except: # Если это точка, то взять координаты точки CoordList.append([float(a[0]), float(a[2]), float(a[4])]) return CoordList

Also in this file the point is indicated, this is the point from which it is necessary to begin counting. The coordinates of the point also received [15.0, 13.0, 5.0]

I tried to create a dictionary of type 1:[координаты линии] but managed only to get the line on which the point is and that does not work correctly.

Here is the code:

 for num, el in enumerate(getCoordinates("AcDbLine\n")): try: point = getCoordinates("AcDbPoint\n")[0] # Получает координаты точки для сравнения except IndexError: # Если точка не найдена, прекратить дальнейшие действия print ("Точка отсчета не найдена") break if point == el[:3] or point == el[4:]: #Если координаты точки совпадают с линией D[1] = [el, GetLength("AcDbLine\n", num)] # Первая линия, которая совпадает с точкой имеет индекс 1

The essence of the problem is to write these coordinates in such a way that they follow each other starting from the point of reference. The starting point can stand anywhere, but at the contact points of two segments.

For greater clarity, I drew a picture. Red numbers indicate the order to be obtained.

Maybe I'm not doing everything right and who will propose a better solution?

So in DXF the point looks

 AcDbPoint 10 15.0 20 13.0 30 5.0 0

and so the line

 AcDbLine 10 15.0 20 10.0 30 5.0 11 15.0 21 13.0 31 5.0 0

Point as a separate element and is set manually just as a line is drawn.

Accepted Answer · 2017-12-15T10:52:44

Try this:

 def to_my_dict(): prev_point = getCoordinates("AcDbPoint\n") if prev_point: point = prev_point[0] else: return "Точка отсчета не найдена" my_dict = {} all_lines = getCoordinates("AcDbLine\n") count = 1 line_count = len(all_lines) while line_count: for el in all_lines: if point == el[:3] or point == el[3:]: my_dict[count] = el # линия, в которой есть точка count += 1 line_count -= 1 if point == el[:3]: point = el[3:] else: point = el[:3] return my_dict print(to_my_dict())

Maybe I did not quite understand you correctly, if this is not what is needed - leave a comment and explain the question in more detail.

With the getCoordinates () function, I can get both a line ("AcDbLine \ n") and a point (AcDbPoint \ n).
It turns out I wanted the first condition to compare the coordinates of a point with the coordinates of the line, and if one line coincides with a point, then assign the key 1 to it. point in the previous line, then assign key 2 and so go through all the lines ... Yes, D dictionary, thanks for the comment) A bit confusing, but I hope I managed to tell a little more clearly.
I edited the answer, substituted your values, it seems to work, note that I replace the next point in the line, maybe I'm wrong

Work with DXF. Python (Sorting coordinates from point of reference)

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