for(i=0;i<10;i++) { console.log(i); }

This code will output a sequence of 0-9.

Question. How to output this sequence (all) in a random order.

I want to see the cleanest and proper implementation

  • one
    And what problem do you solve? - Viktorov
  • one
    Хочется увидеть самую чистую и правильную реализацию - and what are the criteria for purity and correctness? - Andrei NOP
  • The criterion of purity - a small amount of code, correctness - the agreement of the majority of those who understand this - antonin14d '12
  • In general, I do not solve any specific problem, I just wonder - antonin14d
  • 2
    @ antonin14d will correctly fill the array and mix - Alexey Shimansky

3 answers 3

Short, but unfortunately, an uneven distribution method:

 let arr = []; for (let i = 0; i < 10; arr[i] = i++); arr.sort(() => Math.random() - 0.5); console.log(arr);

Alternative, more correct option:

 function shuffle(n) { let arr = []; for (let i = 0; i < n; arr[i] = i++); return arr.map(a => { return { val: a, rnd: Math.random() } }).sort((a, b) => a.rnd - b.rnd).map(a => a.val) } console.log(shuffle(10));

    If it is clean , it is without a zhukveri and anderskor / loudash, then this is how it works correctly : =)

     const range = 10; let used = {}; for (let i = 0; i < range; ++i) { let r = Math.floor(Math.random() * (range - i)); console.log((r in used) ? used[r] : r); let l = range - i - 1; used[r] = (l in used) ? used[l] : l; }

    With lodash will be shorter:

     _.forEach(_.shuffle(_.range(0,10)), function(v) { console.log(v); }); 
     <script src="https://cdn.jsdelivr.net/lodash/4.17.4/lodash.min.js"></script>

      option

       "use strict" const range = 10; let used = Array(range); for (let i = 0; i < range; ++i) { let r = Math.floor(Math.random() * range); let l = used[i] !== void(0) ? used[i] : i; used[i] = used[r] !== void(0) ? used[r] : r; used[r] = l; } console.log(used);