how to convert the minimum double value in fixed format to string
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2 answers
double d = std::numeric_limits<double>::min(); std::string s; int j = 0, count = 0; while(!j) { d *= 10; j = d; s += '0'; ++count; } --count; // нулей после точки s[0] = '.'; std::ostringstream os; os << d; std::string b = os.str(); b.erase(b.find('.'),1); s += b; std::cout << s; // ваш ответ Usually the exponential form (scientific format) is better. It can be displayed immediately:
#include <iomanip> //... std::cout << std::scientific << std::numeric_limits<double>::min(); 
AR Hovsepyan AR Hovsepyan
6.315 2 five 21
- And why is the answer to the point empty? - Stanislav Petrov
- @Stanislav Petrov: if you write double r = .1; the compiler will understand it as 0.1, but if you want to display 0 before the point, it’s not difficult to add a character to the beginning of the line ... - AR Hovsepyan
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Answer:
#include <iostream> #include <sstream> int main() {double number = 0.10; stringstream bla; string str; bla << number; str = bla.str(); } 
Alleksh _ Alleksh _
112 eleven
- the
std::stringstreamis called<sstream>- Fat-Zer - Yes, and 0.10 is far from
std::numeric_limits<double>::min(). - Ternvein
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