char *str3 = new char[SIZE]; str3 = "Amygdala"; delete[] str3; // Здесь ошибка

Please explain what is wrong.

  • Because in c , there are no operators like new , delete , delete[] . - LLENN
  • five
    1) in C there is neither new nor delete . 2) the assignment overwrites the pointer and you try to delete the constant string, not the allocated memory. strcpy(str3, "Amygdala") would be right - Fat-Zer

1 answer 1

What's happening?

 char *str3 = new char[SIZE];

You allocate memory and assign a pointer to this block to the variable str3

 str3 = "Amygdala";

You assign the pointer to a constant string to the variable str3

 delete[] str3;

You are trying to delete a pointer to a constant string.

What do we have to do? It is necessary after the allocation of memory to copy there the necessary content. This can be a function

 strcpy(str3, "Amygdala")

or similar.

And, by the way, you need to compare strings also by content.

 strcpy(str3, "Amygdala"); bool test1 = str3 == "Amygdala"; bool test2 = strcmp(str3, "Amygdala") == 0;

test1 will be false, and test2 true