Android remove an item from an array

Question

I have programmatically created entries, this is TextView and its Checkbox . I need to change the code in order to remove them together under certain conditions. Here is the code to create them:

 ArrayList<LinearLayout.LayoutParams> lParams_r = new ArrayList<LinearLayout.LayoutParams>(); int size_strok_r = 250; int check_left_margin = 125; fontW = 11; lParams_r.add(0, new LinearLayout.LayoutParams(size_strok_r, wrapContent)); lParams_r.get(0).gravity = Gravity.LEFT; ArrayList<LinearLayout.LayoutParams> lParams_check_r = new ArrayList<LinearLayout.LayoutParams>(); lParams_check_r.add(0, new LinearLayout.LayoutParams(size_strok, matchParent)); lParams_check_r.get(0).gravity = Gravity.RIGHT; lParams_check_r.get(0).leftMargin = check_left_margin; ArrayList<LinearLayout> LNew_r = new ArrayList<LinearLayout>(); LNew_r.add(0, new LinearLayout(this)); LNew_r.get(0).setPadding(0, 7, 0, 0); if (first_schet_id == 0) first_schet_id = idbd; ArrayList<TextView> KatNew_r = new ArrayList<TextView>(); KatNew_r.add(0, new TextView(this)); htmlTaggedString = "<u><b>" + str + "</b></u>"; textSpan = android.text.Html.fromHtml(htmlTaggedString); KatNew_r.get(0).setMaxLines(1); KatNew_r.get(0).setId(idbd + 98989); KatNew_r.get(0).setTag(idbd + 98989); KatNew_r.get(0).setText(textSpan); KatNew_r.get(0).setTextSize(fontW); KatNew_r.get(0).setPadding(20, 10, 0, 0); KatNew_r.get(0).setTextColor(getResources().getColor(R.color.white_cl)); KatNew_r.get(0).setTypeface(typeFace); LNew_r.get(0).addView(KatNew_r.get(0), lParams_r.get(0)); ArrayList<CheckBox> CheckNew_r = new ArrayList<CheckBox>(); CheckNew_r.add(0, new CheckBox(this)); CheckNew_r.get(0).setChecked(true); CheckNew_r.get(0).setButtonDrawable(R.drawable.customcheckboxselector); CheckNew_r.get(0).setId(idbd + 99999); CheckNew_r.get(0).setTag(idbd); LNew_r.get(0).addView(CheckNew_r.get(0), lParams_check_r.get(0)); ArrayList<LinearLayout.LayoutParams> lParamsRM = new ArrayList<LinearLayout.LayoutParams>(); lParamsRM.add(0, new LinearLayout.LayoutParams(wrapContent, wrapContent));

And here is how I try to delete:

 removeViewFrom(submenu_right, vibranniSCHET + 98989); removeViewFrom(submenu_right, vibranniSCHET + 99999); public void removeViewFrom(LinearLayout[] views, int id) { for (LinearLayout l : views) { l.removeView(findViewById(id)); } }

Deletion does not work, and I do not know why. Help is needed.

Kirill Malyshev Kirill Malyshev 5.470 one 6 22 · Accepted Answer · 2018-01-28T12:36:17

To remove a View , you must first obtain this View . All elements are contained in two ArrayList for TextView and for CheckBox . As I understand it, vibranniSCHET is the sequence number of the selected item. To match the element number in an ArrayList , add elements to its end, not the beginning:

 KatNew_r.add(new TextView(this)); CheckNew_r.add(new CheckBox(this));

Accordingly, we can simply obtain the element itself by the element number.

Pass one parameter to the method for deletion: the number of the element to be deleted. Lists with TextView and CheckBox can be stored globally. Here is the method for deleting TextView and CheckBox :

 public void removeViewFrom(int position) { TextView textView = KatNew_r.get(position); textView.setVisibility(View.GONE); KatNew_r.remove(position); CheckBox checkBox = CheckNew_r.get(position); checkBox.setVisibility(View.GONE); CheckNew_r.remove(position); }

@ Moonwolf45, in Java it is customary to give names to variables and methods with a small letter.

Android remove an item from an array

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