Print the N first processes, sorted in descending order of cumulative system time. The parameter N is passed as a command line argument.

Closed due to the fact that off-topic participants are Vladimir Martyanov , aleksandr barakin , Viktor Tomilov , AK ♦ , 0xdb 21 Feb '18 at 23:55 .

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1 answer 1

As far as I know, the statistics on the kernel and the user, the ps command does not produce separately. But, if you look at the total time, then something like:

 ps -el | grep -v -e'00:00:00' | awk '{print $13, $14}' | tail -n+2 | sort -r | head -n3

I explain on separate commands of the pipeline:

  • ps -el Provides extended information on all processes.
  • grep -v -e'00: 00: 00 ' Excludes from the list those processes whose time is zero
  • awk '{print $ 13, $ 14}' Displays only the time and name of the program
  • tail -n + 2 Clears the table header.
  • sort -r Sorts descending
  • head -n3 Prints the participants who took the first three places.

Well, you just need to arrange it in the form of a shell script in the last command -n3 (fixed value == 3) with $ 1 - the first parameter in the command line of this script.

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