How to implement a random condition?

Question

There is a random number that sees numbers 0 or 1 . It is necessary between 0 и 1 add the block Angle_Left , and between 1 и 0 Angle_Top how to do?

 var Random = new Random(); for(int i=0;i<20;i++){ float rand = Random.Next(0,2); if(rand == 0){ Console.WriteLine(rand + " — " + "Left"); } if(rand == 1){ Console.WriteLine(rand + " — " + "Top"); }

Example:

 0 - Left - Angle_Left 1 - Top 1 - Top 1 - Top - Angle_Top 0 - Left - Angle_Left 1 - Top - Angle_Top 0 - Left 0 - Left 0 - Left - Angle_Left 1 - Top 1 - Top

Keep in memory the current value of Rand and the previous one.
Before you draw a value based on the current Rand, check the previous one and write an intermediate message based on that.

VladD VladD 183k sixteen 227 433 · Accepted Answer · 2018-03-26T14:42:12

Well, for example:

 Random r = new Random(); IEnumerable<int> GetRandomSequence() { while (true) yield return r.Next(2); } IEnumerable<string> InsertCorners(IEnumerable<int> seq) { int prev = -1; foreach (var curr in seq) { if (prev == 0 && curr == 1) yield return " - Angle_Left"; else if (prev == 1 && curr == 0) yield return " - Angle_Top"; if (curr == 0) yield return "0 - Left"; else if (curr == 1) yield return "1 - Top"; prev = curr; } }

Testing:

 foreach (var s in InsertCorners(GetRandomSequence().Take(20))) Console.WriteLine(s);

gives out

 0 - Left 0 - Left 0 - Left 0 - Left - Angle_Left 1 - Top 1 - Top 1 - Top - Angle_Top 0 - Left 0 - Left - Angle_Left 1 - Top 1 - Top - Angle_Top 0 - Left 0 - Left - Angle_Left 1 - Top 1 - Top 1 - Top - Angle_Top 0 - Left 0 - Left 0 - Left - Angle_Left 1 - Top

what is necessary, thank you very much)) and if you still have to do in the very beginning Angle_Left or Angle_Top or Left or Top ?
the first line in the result can be 0 - Left or 1 - Top yes?
you can also randomly type it on Angle_Left or Angle_Top But only the first line

How to implement a random condition?

1 answer 1

More articles: