Form submission by Ajax

Question

Here is the code:

$(document).ready(function () { var options = { target: "#output", beforeSubmit: showRequest, success: showResponse, timeout: 3000 }; // привязываем событие submit к форме $('#form').submit(function () { $(this).ajaxSubmit(options); return false; }); // ---- Форма ----- }); // вызов перед передачей данных function showRequest(formData, jqForm, options) { return true; } // вызов после получения ответа function showResponse(responseText, statusText) {}

Jquery and jquery.form are connected. In the handler .submit(fn) fn returns false, as you can see, but the form is sent 2 times. How to prevent re-sending?

And what should it return if return false explicitly stated in it?))
This most false should prevent the default browser from working.
Isn't it better to use event.preventDefault () for these purposes?

Alex Kapustin Alex Kapustin 11.1k 12 nineteen · Accepted Answer · 2012-02-16T11:02:38

read to enlightenment.

Or we do not hang the event on $('#form').submit

either in

 $('#form').submit(function () { //перебираем все елементы формы и отправляем c помощью $.post(...) }

See linkexchanger.su/2008/45.html I took the script from there.

Form submission by Ajax

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