How to parse a JSON object correctly

Question

Perhaps such a question was asked, but I did not find ((. Help to create a model for this type of json, I get the answer in the form of an object, I would disassemble the array without any problems.

{ "0": { "id": "1", "name": "Антон", "birthday": { "year": "1978", "month": "03", "day": "05", "zodiac": { "name": "Рыбы" } } }, "1": { "id": "2", "name": "Наталия", "birthday": { "year": "1973", "month": "05", "day": "23", "zodiac": { "name": "Близнецы" } } }, "2": { "id": "3", "name": "Света", "birthday": { "year": "1991", "month": "04", "day": "14", "zodiac": { "name": "Овен" } } }, "execution_time": 0.1185 }

They increase by +1 as needed, they can reach 100 and 200, that's why I can't figure it out

Answer 1 · 2018-05-26T14:05:59

I suppose you already have a certain class Person .

Write your deserializer

 class PersonsDeserializer : JsonDeserializer<List<Person>> { override fun deserialize(json: JsonElement, typeOfT: Type, context: JsonDeserializationContext): List<Person> { val persons = ArrayList<Person>() for (entry in json.asJsonObject.entrySet()) { try { persons.add(context.deserialize<Person>(entry.value, Person::class.java)) } catch (ignore: JsonParseException) { } } return persons } }

To apply

 @JsonAdapter(PersonsDeserializer.class) data class PersonsResponse : ArrayList<Person>

It should work)

Kotlin code

I'm not writing on Kotlin, and the lower class either, I posted a screenshot for better visibility
The bottom class needs to be got and inherit from ArrayList.
The most important thing for me is to understand how to create a model correctly, if not difficult to please, I will be very grateful
The bottom class is the @JsonAdapter(PersonsDeserializer.class) class PersonsResponse extends ArrayList<Person> model @JsonAdapter(PersonsDeserializer.class) class PersonsResponse extends ArrayList<Person>

How to parse a JSON object correctly

1 answer 1

More articles: