I don’t figure out how to do something ... In general, there is a variable that contains a string of text. It is necessary in this line to replace *.css with template/*.css .
Dmitriy Simushev
15.5k 3 38 75
Andrey Talanin Andrey Talanin
891 eight 23
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2 answers
$str = preg_replace('/([^/]+\.css)/', 'template/$1', $str); 
Sh4dow Sh4dow
13.8k sixteen 33
- As I understand it, the asterisk is an element of the string. Those.
$str = preg_replace('/\*\.css/', 'template/$0', $str);- alexlz - It gives an error, but based on this, I got what I need, thank you. [code] $ page = preg_replace ("/ ([- a-zA-Z0-9] + \. css) /", "template / $ 1", $ page); [/ code] - Andrey Talanin
- I beg your pardon, I forgot the parenthesis, yes - Sh4dow
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$str = str_replace("*.css", "template/*.css", $str); 
barsukov barsukov
345 3 9
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