Tell me how to implement the function:

int test(...){ printf(...);}

That is, pass the va_list parameters to the next function.

    2 answers 2

    It's just impossible to pass an undefined list of arguments, there is no syntax for this in the language. However, the problem can be circumvented, as indicated here : the function to which you transfer control must have an option that accepts va_list .

    For your case, you can use vprintf :

     void test(char *format, ...) // должен быть хотя бы один аргумент { va_list args; va_start(args, format); vprintf(format, args); va_end(args); }

      Or macro:

        #define prn(A,...) printf(A,__VA_ARGS__)

      sometimes it's easier, especially if you need to add additional arguments to VA_ARGS. But for the mind, you still need to learn about the VA_ * interface .