How to write a regular expression that removes all characters except numbers and the + character?

  • /[^\d\+]/g ? (2 characters) - user218976

2 answers 2

 /[^+\d]/g
  • [...] - character class
  • ^ - inversion, we will replace "everything except"
  • + - the + symbol, you can screen: \+ , but inside the character class it is not necessary
  • \d - digit
  • /.../g - global flag for replace - change all occurrences

 let str = 'call: +7(123) 456-78-90'; console.log(str.replace(/[^+\d]/g, ''));

  • Plus not shielded. - user218976
  • And why should it be screened in a character class ?? - vp_arth
  • one
    @Anamnian and why should it be screened in this case (in the character set)? - Regent
  • You are right, I was wrong. It is not necessary to screen it. Although it is clearer to me with shielding. - user218976
  • 2
    @Anamnian ... then, it means that at some point in the development something went wrong, since such a regression appeared :) For I do not want to sit around to understand and correct errors in such an expression from the word "completely". And, I think, + instead of \+ in [] when parsing it will be the lesser of problems - Regent

Let's go from the reverse, just take any character except the number and +

 const regEx = /[^\d\+]/g; const test = '123gybbrry45ybg6=789,m er+' console.log(test.replace(regEx, ''));