Why does the scanf_s function in Visual Studio stop working in the C language when using “% s”?

Question

Why does the scanf_s function in Visual Studio 2013 stop using the C language when using "% s"?

char name[40]; scanf_s("%s", name);

Then, when I entered the data into the console, I press enter, and I see the message “Termination of work”.

Pavel Mayorov Pavel Mayorov 48.9k five 50 110 · Accepted Answer · 2015-08-05T18:35:22

Because scanf_s requires specifying the size of all buffers transferred to it.

 scanf_s("%s", name, 40);

Pavel Mayorov

48.9k five 50 110

And how to cope if it is scanf ("% s% d", how can I write?); if there are two variables? - Maksym Suprunenko
one
Please read the documentation. - Pavel Mayorov
msdn.microsoft.com/ru-ru/library/w40768et%28v=vs.120%29.aspx - Pavel Mayorov

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0xdb 9,969 ten 31 63 · Answer 2 · 2018-03-25T17:06:50

You must specify the _countof (имя переменной куда считываешь) parameter _countof (имя переменной куда считываешь) , for example:

 scanf_s("%s",&name,_countof(name));

2 answers 2