PyQT window show hotkeys

Question

It is not possible to implement the demonstration window by hotkeys. I want to achieve the following: the window was minimized; by pressing the hot keys, the window changes to the show state.

I use PyQT and the keyboard library to intercept the keyboard. In a separate thread, I expect a keystroke (in this case, esc), and then show the window.

The window freezes and crashes. Perhaps because I work with a GUI from another thread. How can I solve the problem?

import sys from PyQt5.QtWidgets import QWidget, QApplication, QSystemTrayIcon, QStyle import keyboard import threading class ScreenArea(QWidget): def __init__(self): super().__init__() self.setMinimumSize(500, 500) # Устанавливаем размеры #self.show() def show(w): while True: keyboard.wait('esc') w.show() app = QApplication(sys.argv) w = ScreenArea() threading.Thread(target=show, args=(w,)).start() sys.exit(app.exec_())

Answer 1 · 2018-09-16T17:01:24

I don't have a keyboard library, but I have a pynput library, which is designed for the same purposes.

The example below is working, press the esc and space keys. How much is it thread safe? I think no.

I added processing of some events: the symbol c and C ; the alt_l key, as well as the key combination ( Alt_l+c , Alt_l+C , Alt_r+c , Alt_r+C ). Try it.

 import sys from PyQt5.QtWidgets import QWidget, QApplication, QSystemTrayIcon, QStyle #import keyboard from pynput import keyboard # pip install pynput import threading class ScreenArea(QWidget): def __init__(self): super().__init__() self.setMinimumSize(500, 500) self.show() def show(w): # Ключевые комбинации для проверки COMBINATIONS = [ {keyboard.Key.alt_l, keyboard.KeyCode(char='c')}, # Alt_l + c {keyboard.Key.alt_l, keyboard.KeyCode(char='C')}, # Alt_l + C {keyboard.Key.alt_r, keyboard.KeyCode(char='c')}, # Alt_r + c {keyboard.Key.alt_r, keyboard.KeyCode(char='C')} # Alt_r + C ] # # текущий активный модификатор current = set() def executeAltC(): print ("\n *** Нажата комбинация клавиш: Alt+C\n *** Сделайте что-нибудь :)") def get_key_name(key): """ Функцию get_key_name(), будет проверять тип ключа. Для нормального ключа он вернет key.char, у которого не будет дополнительных одинарных кавычек. Для других ключей он напечатает имя ключа (например, Key.cmd, Key.alt, Key.ctrl ...) """ if isinstance(key, keyboard.KeyCode): return key.char else: return str(key) def on_press(key): key_name = get_key_name(key) if key == keyboard.Key.esc: print('--- Нажата клавиша: {}'.format(key_name)) w.hide() elif key == keyboard.Key.space: print('--- Нажата клавиша: {}'.format(key_name)) w.show() elif key == keyboard.Key.alt_l: print('--- Нажата клавиша: {}'.format(key_name)) # KeyCode события нажатия символа elif (key == keyboard.KeyCode.from_char('c')) or \ (key == keyboard.KeyCode.from_char('C')): print('--- Нажата клавиша: {}'.format(key_name)) else: print('Информационно. Вы нажали: {}'.format(key_name)) current.clear() # Клавиши-модификаторы. Alt_l+c, Alt_l+C, Alt_r+c, Alt_r+C # any(iterable) -> bool. Проверяет, есть ли среди указанных элементов # хотя бы один, принимающий значение `истина` if any([key in COMBO for COMBO in COMBINATIONS]): current.add(key) if any(all(k in current for k in COMBO) for COMBO in COMBINATIONS): executeAltC() current.clear() with keyboard.Listener(on_press=on_press) as listener: listener.join() app = QApplication(sys.argv) w = ScreenArea() threading.Thread(target=show, args=(w, ), daemon=True).start() # + daemon=True sys.exit(app.exec_())

It's not strange, I did the same not the keyboard and it does not work.
Using the library doesn’t matter to me) I don’t really understand how to catch the events of pressing a character on the keyboard?
Alt I catch without problems (keyboard.Key.alt), but how to catch the "c" character?
@chessinvin I added a code on questions you are interested in.

PyQT window show hotkeys

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