Split the sequence into groups of 5 characters SI

The length of the sequence is no more than 100 characters. It is considered that the sequence is read all, if 100 characters have already been read, or any other number of elements specified in advance by the user. Split the sequence into groups of 5 characters (in the last group, how many remain) and output each sequence in the reverse order.

Since we just started to study C, then there is almost no information on the Internet about how to do this by simple operators like the scan. I have presented an algorithm, but the program gives an incorrect answer, maybe you can figure out where the error is

#include #include #include #include #define N 100 int main() { int i, n,a,b; char C[N]; setlocale(0, ""); printf("Введите количество символов\n"); if (scanf("%d", &n) == 0) { printf("Введен символ\n"); getch(); return 0; } if (n > N || n <= 0) { printf("Недопустимое число элементов\n"); getch(); return 0; } fflush(stdin); printf("Введите массив элементов\n"); for (i = 0; i < n; i++) { scanf("%c", &C[i]); } printf("Вы ввели: \n"); for (i = 0; i < n; i++) { printf("%c ", C[i]); } printf("\nЭлементы после сортировки \n"); for (i = 0; i < n; i++) if (i+4 <= n) { a = i+4; for (a; a > i; a--) { printf("%c ", C[a]); } } else { a = i; for (n; n > a; n--) { printf("%c ", C[n]); } } getch(); return 0; }