define ('HOST', 'localhost'); define ('USER', 'root'); define ('PASS', '12345'); define ('DB', '*****'); $connect = mysqli_connect(HOST, USER, PASS, DB); if ( !$connect ) die('Ошибка подключения к БД'); if(isset($_POST['submit'])){ $login = $_POST['username']; $password = $_POST['password']; $r_password = $_POST['rpass']; } if(isset($_POST['submit'])){ $query2 = mysqli_query($connect, "SELECT * FROM signup WHERE username = $login "); $user_data = mysqli_fetch_array($query2); if($user_data['username'] != ($query2)){ echo "Vi zaregani"; $check = true; if ($check == true){ $query = mysqli_query($connect, "INSERT INTO signup username) VALUES ('$login')"); } } else{ echo "NET"; } if(isset($_POST['submit'])){ if($password == $r_password){ //$password = md5($password); $query = mysqli_query($connect, "INSERT INTO signup (username, password) VALUES ('$login','$password')"); } }

Tried to write a script did not think of HELP

  • $ user_data ['username'] and $ query2 cannot be compared, so returns the object mysqli_result or false php.net/manual/ru/mysqli.query.php - Jean-Claude
  • compare login form $ _POST ['username'] and $ user_data ['username'] from bazka - Jean-Claude

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