How to capture a variable number of arguments lambda?

template <typename... Args> void foo(Args... args) { auto lambda = [](){}; // как захватить args? }
  • 2
    Describe your question in more detail, add details, an existing code. At the moment, to understand the essence of the question is difficult. - Komdosh
  • @Komdosh added - rex
  • one
    @nick_n_a you ask me to show how to do what I ask)? - rex
  • one
    Already found the answer on the question word stack stackflow.com/questions/16527595/…, next time I will ask for enSO - rex
  • one
    @ARHovsepyan "and the example is given" - excuse me, where did you find him there in the first edition? See the timeline . - 0xdb

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