a = input() if a<=3: print("You are a baby") elif a>3 and a<18: print("You are a teenager") else : if 18 >= a and a<60: print("You are an adult") else: if a>=60: print("You are an elder") input()

Closed due to the fact that off-topic participants 0xdb , Sergey Gornostaev , gil9red , Kromster , andreymal 8 December '18 at 12:48 .

It seems that this question does not correspond to the subject of the site. Those who voted to close it indicated the following reason:

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    Add the full text of the error to the question. - Sergey Gornostaev

2 answers 2

The input() function always returns a string value. You get an error because the conditional operator <= cannot compare the string and the number and therefore produces a TypeError error.

If you want to use a as a number, do this:

 a = int(input())
  • Thank!!!!!!!! - Artem Titov
 a = int(input()) if a<=3: print("You are a baby") elif a>3 and a<18: print("You are a teenager") elif a>18 and a <60: print("You are an adult") else: print("You are an elder")

It seems to work. Python very responsive to snoops