How to make it so that when you change a select (it is sent to record types) Change to the values ​​of the record you choose. Fields in all entries are the same. Help please, I'm just starting to understand, and don't hit the curve code.

<?php $parsingGreec = new stdClass; foreach ((array) get_post_meta('33688') as $k => $v) { $parsingGreec->$k = $v[0]; } ?> <?php $args = array( 'numberposts' => 0, 'post_type' => 'parsing' ); $catPosts = get_posts($args); echo '<form method="POST">'; echo '<select>'; foreach ($catPosts as $singlePost) { echo '<option>'.$singlePost->post_title. '' .get_post_meta($catPosts).'</option>'; }; echo '</select>'; echo ''; echo '</form>'; print_r($catPosts); ?> <div class="flex_grid"> <form method="POST" id="form_post"> <label for="lft_after_before_field">C какого числа: </label> <input type="text" id= "lft_after_field" name="startdata" value="<?echo $parsingGreec->month_after_value_key ?>" size="25" /> <label for="lft_after_before_field">По какое число: </label> <input type="text" id= "lft_before_field" name="enddata" value="<?echo $parsingGreec->month_before_value_key ?>" size="25" /> <label for="lft_after_before_field">Количество ночей: </label> <input type="text" id= "lft_night_field" name="night" value="<?echo $parsingGreec->parsing_night_key ?>" size="25" /> <button type="submit" value="parsing">Спарсить</button> <?php print_r($_POST['lft_before_field']); ?> </form>

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