Given the file f, the components of which are integers. Retrieve file g formed from file f with the exception of repeated occurrences of the same number.

Here is my code

import re f = open ("f.txt","r+") n = f.read() nums = set(re.findall('-?\d+', n)) g = open("g.txt","w+") lst=[] for a in nums: lst.append(a) g.write(a) g.close() g = open('g.txt', 'r+') m = g.read() # num1= ', '.join(nums) print("Исходные числа в файле f: ",n) print("Числа в файле g: ",num1) g.close f.close

The result of the program

 Исходные числа в файле f: 234, -5 , 45, 2, 234, 0, 0 Числа в файле g: 0, 234, -5, 2, 45

The program works, but you need to redo it so that f.read () is not in the variable n. You also need to make the input numbers in the fc file keyboard. How can I change the code to fix these problems?

Closed due to the fact that off-topic participants Kromster , 0xdb , aleksandr barakin , Enikeyschik , iluxa1810 28 Dec '18 at 7:23 .

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1 answer 1

The program works, but you need to redo it so that f.read () is not in the variable n. You also need to make the input numbers in the fc file keyboard.

Replace:

 n = f.read()

On

 n = input("Input: ")