In the python requests module there is the following construction:
r = requests.get("https://google.com") r.text #получение html кода страницы Question:
How to perform this action in python using a standard (or not) browser in the system?
To solve the problem I used selenium:
from selenium import webdriver driver = webdriver.Firefox() driver.get("https://google.com") driver.page_source Source: https://ru.stackoverflow.com/questions/931257/
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