What does it mean not to get 0.71? IAZ gave you a link where it is clearly defined what and where. Conversion to binary fractions differs from similar conversion of integers.
In your example, 245.71:
We translate 245 - we can do it.
Now according to the algorithm (in parentheses - the binary number):
0.71x2 = 1.42 (1) [0.5]
0.42x2 = 0.84 (0) [0.25]
0.84x2 = 1.68 (1) [0.125]
0.68x2 = 1.36 (1) [0.0625]
0.36x2 = 0.72 (0) [0.03125]
0.72x2 = 1.44 (1) [0.015625]
0.44x2 = 0.88 (0) [0.0078125]
0.88x2 = 1.76 (1) [0.00390625]
0.76x2 = 1.52 (1) [0.001953125]
0.52x2 = 1.04 (1) [0.0009765625]
We 1x0.5 + 0x0.25 + 1x0.125 + 1x0.0625 + 0x0.03125 + 1x0.015625 + 0x0.0078125 + 1x0.00390625 + 1x0.001953125 + 1x0.0009765625 = 0,7099609375 : 1x0.5 + 0x0.25 + 1x0.125 + 1x0.0625 + 0x0.03125 + 1x0.015625 + 0x0.0078125 + 1x0.00390625 + 1x0.001953125 + 1x0.0009765625 = 0,7099609375 (further calculations depend on required accuracy). Here is your number in binary 11110101.1011010111 .
Tell me, what is really in this expression "0x2^-3 + 0x2^-2 + 0x2^-1" turns out 0.625? As for me so there, this type of zero. You are probably the unit in the second digit lost. But even in this case, 0.625 somehow does not work. In general, something you namudri or I do not understand something.
